6m^2-11m-95=0

Solution for 6m^2-11m-95=0 equation:

6m^2-11m-95=0

a = 6; b = -11; c = -95;
Δ = b2-4ac
Δ = -112-4·6·(-95)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-49}{2*6}=\frac{-38}{12}
=-3+1/6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+49}{2*6}=\frac{60}{12}
=5
$